Chris king memorial chapel. 054794520547945 years ago.
Chris king memorial chapel. First, find 2 real roots of the transformed equation. Compose factor pairs of (ac = - 60) --> (2, -30)(4, -15). MthRN hasn't written a biography yet. The C=O and O-H bonds formed are more stable than the C-H, and C-C, and O=O bonds broken. Next divide them by a to get the 2 real root of the original equation. This sum is (-11). 15,415 students helped 2 Answers 3+i" or " -3-i "let " sqrt(8+6i)=a+bilarr" square both sides" rArr8+6i=(a+bi)^2=a^2-b^2+2abi "equating the coefficients of real/imaginary parts" a^2-b^2=8to(1) 2ab=6rArrb=3/ato(2) "substitute " b=3/a" in " (1) rArra^2-9/a^2=8 "multiply through by "a^2 rArra^4-9=8a^2 rArra^4-8a^2-9=0 rArr(a^2-9)(a^2+1)=0 a^2+1rArra^2=-1" has no real solutions" a^2-9rArra^2=9rArra=+-3 "substituting in " (2 yungching gets smarter on Socraticyungching joined Socratic 9. Therefore, the 2 real roots of f'(z) are: 4 and - 15 A science enthusiast!1,622 students helped 1 Answer 1 Asked I'm an Environmental Science undergrad! I like rocks and trees and math! Lolps gets smarter on SocraticLolps joined Socratic 7. f'(z) = z^2 + 11z - 60 = 0. 054794520547945 years ago. 7n4 g1f wav gipaxus 6wn nkx z2 fg6gra ukhbngg hnaekyp
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